m^2-3m-630=0

Solution for m^2-3m-630=0 equation:

m^2-3m-630=0

a = 1; b = -3; c = -630;
Δ = b2-4ac
Δ = -32-4·1·(-630)
Δ = 2529
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{2529}=\sqrt{9*281}=\sqrt{9}*\sqrt{281}=3\sqrt{281}$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-3)-3\sqrt{281}}{2*1}=\frac{3-3\sqrt{281}}{2}
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-3)+3\sqrt{281}}{2*1}=\frac{3+3\sqrt{281}}{2}
$